1. Find Solution of an equation 1/x using Simpson's 1/3 rule
x1 = 1 and x2 = 2
Step value (h) = 0.25Solution:Equation is `f(x)=(1)/(x)`.
The value of table for `x` and `y`
| x | 1 | 1.25 | 1.5 | 1.75 | 2 |
|---|
| y | 1 | 0.8 | 0.6667 | 0.5714 | 0.5 |
|---|
Method-1:Using Simpsons `1/3` Rule
`int y dx=h/3 [(y_0+y_4)+4(y_1+y_3)+2(y_2)]`
`int y dx=0.25/3 [(1 +0.5)+4xx(0.8+0.5714)+2xx(0.6667)]`
`int y dx=0.25/3 [(1 +0.5)+4xx(1.3714)+2xx(0.6667)]`
`int y dx=0.25/3 [(1.5)+(5.4857)+(1.3333)]`
`int y dx=0.6933`
Solution by Simpson's `1/3` Rule is `0.6933`
Method-2:Using Simpsons `1/3` Rule
`int y dx=h/3 [y_0+4y_1+2y_2+4y_3+y_4]`
`y_0=1`
`4y_1=4*0.8=3.2`
`2y_2=2*0.6667=1.3333`
`4y_3=4*0.5714=2.2857`
`y_4=0.5`
`int y dx=0.25/3*(1+3.2+1.3333+2.2857+0.5)`
`int y dx=0.25/3*(8.319)`
`int y dx=0.6933`
Solution by Simpson's `1/3` Rule is `0.6933`
This material is intended as a summary. Use your textbook for detail explanation.
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