Formula
1. Weddle's Rule
`int y dx = (3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)+(y_6+5y_7+y_8+6y_9+y_10+5y_11+y_12)+...]`
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Examples
1. Find Solution using Weddle's rule
| x | f(x) |
| 7.47 | 1.93 |
| 7.48 | 1.95 |
| 7.49 | 1.98 |
| 7.50 | 2.01 |
| 7.51 | 2.03 |
| 7.52 | 2.06 |
| 7.53 | 2.09 |
Solution:The value of table for `x` and `y`
| x | 7.47 | 7.48 | 7.49 | 7.5 | 7.51 | 7.52 | 7.53 |
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| y | 1.93 | 1.95 | 1.98 | 2.01 | 2.03 | 2.06 | 2.09 |
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Method-1:Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`
`int y dx=(3xx0.01)/10 [(1.93 + 5xx1.95 + 1.98 + 6xx2.01 + 2.03 + 5xx2.06 + 2.09)]`
`int y dx=(3xx0.01)/10 [40.14]`
`int y dx=0.1204`
Solution by Weddle's Rule is `0.1204`
Method-2:Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`
`y_0=1.93`
`5y_1=5*1.95=9.75`
`y_2=1.98`
`6y_3=6*2.01=12.06`
`y_4=2.03`
`5y_5=5*2.06=10.3`
`y_6=2.09`
`int y dx=(3xx0.01)/10*[(1.93+9.75+1.98+12.06+2.0310.3+2.09)]`
`int y dx=(3xx0.01)/10*(40.14)`
`int y dx=0.1204`
Solution by Weddle's Rule is `0.1204`
This material is intended as a summary. Use your textbook for detail explanation.
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