2. Find Solution using Weddle's rule

x	f(x)
0	1
1	0.5
2	0.2
3	0.1
4	0.0588
5	0.0385
6	0.027

Solution:
The value of table for `x` and `y`

x	0	1	2	3	4	5	6
y	1	0.5	0.2	0.1	0.0588	0.0385	0.027

Method-1:
Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`

`int y dx=(3xx1)/10 [(1 + 5xx0.5 + 0.2 + 6xx0.1 + 0.0588 + 5xx0.0385 + 0.027)]`

`int y dx=(3xx1)/10 [4.5783]`

`int y dx=1.3735`

Solution by Weddle's Rule is `1.3735`

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Method-2:
Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`

`y_0=1`

`5y_1=5*0.5=2.5`

`y_2=0.2`

`6y_3=6*0.1=0.6`

`y_4=0.0588`

`5y_5=5*0.0385=0.1925`

`y_6=0.027`

`int y dx=(3xx1)/10*[(1+2.5+0.2+0.6+0.05880.1925+0.027)]`

`int y dx=(3xx1)/10*(4.5783)`

`int y dx=1.3735`

Solution by Weddle's Rule is `1.3735`

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