1. Find Solution of an equation 1/x using Weddle's rule
x1 = 1 and x2 = 2
Interval N = 6

Solution:
Equation is `f(x)=(1)/(x)`.

`h = (b-a)/N`

`h = (2 - 1) / 6 = 0.1667`

The value of table for `x` and `y`

x	1	1.1667	1.3333	1.5	1.6667	1.8333	2
y	1	0.8571	0.75	0.6667	0.6	0.5455	0.5

Method-1:
Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`

`int y dx=(3xx0.1667)/10 [(1 + 5xx0.8571 + 0.75 + 6xx0.6667 + 0.6 + 5xx0.5455 + 0.5)]`

`int y dx=(3xx0.1667)/10 [13.863]`

`int y dx=0.6931`

Solution by Weddle's Rule is `0.6931`

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Method-2:
Using Weddle's Rule
`int y dx=(3h)/10 [(y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6)]`

`y_0=1`

`5y_1=5*0.8571=4.2857`

`y_2=0.75`

`6y_3=6*0.6667=4`

`y_4=0.6`

`5y_5=5*0.5455=2.7273`

`y_6=0.5`

`int y dx=(3xx0.1667)/10*[(1+4.2857+0.75+4+0.62.7273+0.5)]`

`int y dx=(3xx0.1667)/10*(13.863)`

`int y dx=0.6931`

Solution by Weddle's Rule is `0.6931`

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