4. Find Solution of an equation 2x^3-4x+1 using Trapezoidal rule
x1 = 2 and x2 = 4
Step value (h) = 0.5

Solution:
Equation is `f(x)=2x^3-4x+1`.

The value of table for `x` and `y`

x	2	2.5	3	3.5	4
y	9	22.25	43	72.75	113

Method-1:
Using Trapezoidal Rule
`int y dx=h/2 [y_0+y_4+2(y_1+y_2+y_3)]`

`int y dx=0.5/2 [9 +113 + 2xx(22.25+43+72.75)]`

`int y dx=0.5/2 [9 +113 + 2xx(138)]`

`int y dx=0.5/2 [9 +113 + 276]`

`int y dx=99.5`

Solution by Trapezoidal Rule is `99.5`

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Method-2:
Using Trapezoidal Rule
`int y dx=h/2 [y_0+2y_1+2y_2+2y_3+y_4]`

`y_0=9`

`2y_1=2*22.25=44.5`

`2y_2=2*43=86`

`2y_3=2*72.75=145.5`

`y_4=113`

`int y dx=0.5/2*(9+44.5+86+145.5+113)`

`int y dx=0.5/2*(398)`

`int y dx=99.5`

Solution by Trapezoidal Rule is `99.5`

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