Find Column Space ...
`[[1,2,3,2],[3,0,1,8],[2,-2,-2,6]]`

Solution:

	`1`	`2`	`3`	`2`
	`3`	`0`	`1`	`8`
	`2`	`-2`	`-2`	`6`

Now, reduce the matrix to row echelon form
interchanging rows `R_1 harr R_2`

=	`3` `0` `1` `8` `1` `2` `3` `2` `2` `-2` `-2` `6`

`R_2 larr R_2-1/3xx R_1`

=	`3` `0` `1` `8` `0` `2` `8/3` `-2/3` `2` `-2` `-2` `6`

`R_3 larr R_3-2/3xx R_1`

=	`3` `0` `1` `8` `0` `2` `8/3` `-2/3` `0` `-2` `-8/3` `2/3`

`R_3 larr R_3+ R_2`

=	`3` `0` `1` `8` `0` `2` `8/3` `-2/3` `0` `0` `0` `0`

The rank of a matrix is the number of non all-zeros rows
`:. Rank = 2`

Column Space :
The matrix has 2 pivots and Pivots are in the columns 1 and 2.
We know that these columns in the original matrix define the column space of the matrix.
`:.` The Column Space is

`[[1],[3],[2]],[[2],[0],[-2]]`

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