


Method and examples


Geometric Progression 



Problem 10 of 23 


10. Find arithmetic mean between and .










Solution 
Solution provided by AtoZmath.com


Want to know about

This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
Geometric Progression 
10. Find 6 arithmetic mean between 3 and 24 .
Let ` A_1, A_2, A_3, A_4, A_5, A_6` be the `6` arithmetic mean between `3` and `24`.
`:. 3, A_1, A_2, A_3, A_4, A_5, A_6, 24` are in AP .
Here First term `a = 3` and Last term `b = 24`
Comman difference `d = (ba)/(n+1) = (243)/(6+1) = 21/7 = 3`
`:.` Required Arithemetic Means,
`A_1 = T_2 = a + d = 3 + 3 = 6`
`A_2 = T_3 = a + 2d = 3 + 2(3) = 9`
`A_3 = T_4 = a + 3d = 3 + 3(3) = 12`
`A_4 = T_5 = a + 4d = 3 + 4(3) = 15`
`A_5 = T_6 = a + 5d = 3 + 5(3) = 18`
`A_6 = T_7 = a + 6d = 3 + 6(3) = 21`





Share with your friends, if solutions are helpful to you.


