1. Find AreaTriangle(A,B)
`A=(1,2,3)`,`B=(4,5,6)`

Solution:
Here `vec A=(1,2,3),vec B=(4,5,6)`

Area `=1/2|vec A xx vec B|`

1. Calculate cross product
`vec A xx vec B`

`=|[i,j,k],[A_1,A_2,A_3],[B_1,B_2,B_3]|`

`=|[i,j,k],[1,2,3],[4,5,6]|`

`=i(2xx6-3xx5)-j(1xx6-3xx4)+k(1xx5-2xx4)`

`=i(12-15)-j(6-12)+k(5-8)`

`=-3i+6j-3k`

`=(-3,6,-3)`

2. Calculate magnitude
`|vec vec A xx vec B|`

`=sqrt((-3)^2 + 6^2 + (-3)^2)`

`=sqrt(9 + 36 + 9)`

`=sqrt(54)`

`=7.3485`


3. Calculate triangle area
Area `=1/2 * 7.3485=3.6742`