|
|
|
|
|
|
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
|
|
Ratio and Proportion - If a/b=c/d then prove that (2a+3c)/(2b+3d)=(5a-4c)/(5b-4d) calculator
|
1. If `a:b:c=2:3:5` then find value of `(a^2+b^2+c^2)/(ab+bc+ca)`
 1. If `a/b=2/3`, then find `(2a-3b)/(a-2b)`
2. If `a:2=b:3=c:5`, then find `(a^2+b^2+c^2)/(ab+bc+ca)`
3. If `a/4=b/15`, then find `(a+b)/(a-b)`
4. If `(2a+3b)/(a+b)=13/5`, then find `a/b`
5. If `(x^2+1)/(x^2-1)=2`, then find `x`
6. If `x:30=12:20`, then find `x`
2. If `a:b=2:3,b:c=4:5` then find `a:b:c`
1. If `a:b=2:3,b:c=4:5`, then find `a:b:c`
2. If `b:c=4:5,c:d=5:6`, then find `b:c:d`
3. If `a:b=2:3,b:c=4:5,c:d=5:6`, then find `a:b:c:d`
4. If `2a=3b`, then find `a:b`
5. If `2a=3b=7c`, then find `a:b:c`
3. If `a/b=c/d=e/f` then prove that `(2a+3c-4e)/(2b+3d-4f)=(5a-4c+3e)/(5b-4d+3f)`
1. If `a/b=c/d=e/f`, then prove that `(2a+3c-4e)/(2b+3d-4f)=(5a-4c+3e)/(5b-4d+3f)`
2. If `x/(b^2-c^2)=y/(c^2-a^2)=z/(a^2-b^2)`, then prove that `x+y+z=0`
4. If `x/(y+z)=y/(z+x)=z/(x+y)` then prove the value of each ratio is `1/2` or `-1`
1. If `x/(y+z)=y/(z+x)=z/(x+y)`, then prove each ratio = `1/2,-1`
2. If `(5a+6b)/(7c)=(6b+7c)/(5a)=(7c+5a)/(6b)`, then prove each ratio = `2,-1`
3. If `(ax+by)/(x+y)=(ay+bz)/(y+z)=(az+bx)/(z+x)`, then prove each ratio = `(a+b)/2`
5. Geometric Mean
1. Geometric Mean of `49/4` and `16/9`
2. Geometric Mean of `8a^2` and `32b^2`
3. Geometric Mean of `(a-b)^2` and `(a+b)^2`
4. If geometric mean `6x^2` and x is `9x`, find value of x
6. Ratios(duplicate, triplicate) and proportional(mean, third, fourth)
1. Duplicate ratio of 2:3
2. Triplicate ratio of 2:3
3. Sub-Duplicate ratio of 16:25
4. Sub-Triplicate ratio of 8:27
5. Compounded ratio of 2:5,3:4
6. Compounded ratio of 2:3,3:4,4:5
7. Mean proportional of 8,32
8. Third proportional of 16,36
9. Fourth proportional of 3,7,15
10. Compare ratios of 2:3,3:4,4:5
|
Example1. If `a/b=c/d=e/f` then prove that `(2a+3c-4e)/(2b+3d-4f)=(5a-4c+3e)/(5b-4d+3f)`
Solution:
`a/b=c/d=e/f`
Suppose, `a/b=c/d=e/f=k` (say)
`:. a=bk,c=dk,e=fk`
Now LHS`=(2a+3c-4e)/(2b+3d-4f)`
`=(2bk+3dk-4fk)/(2b+3d-4f)`
`=(k(2b+3d-4f))/(2b+3d-4f)`
`"Now cancel the common factor "(2b+3d-4f)`
`=k`
Now RHS`=(5a-4c+3e)/(5b-4d+3f)`
`=(5bk-4dk+3fk)/(5b-4d+3f)`
`=(k(5b-4d+3f))/(5b-4d+3f)`
`"Now cancel the common factor "(5b-4d+3f)`
`=k`
|
|
|
|
|
|
