1. Find next 3 numbers in the sequence `61,52,63,94,46`

Here each number is reverse of the square of the numbers
`4^2=16 => 61`

`5^2=25 => 52`

`6^2=36 => 63`

`7^2=49 => 94`

`8^2=64 => 46`

So required number are
`9^2=81 => 18`

`10^2=100 => 001`

`11^2=121 => 121`

Answer : `18,001,121`

`:.` The next 3 number for given series `61,52,63,94,46` are `18,001,121`

Solution-1

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2. Find next 3 numbers in the sequence `1,4,9,61,52`

Here each number is reverse of the square of the numbers
`1^2=1 => 1`

`2^2=4 => 4`

`3^2=9 => 9`

`4^2=16 => 61`

`5^2=25 => 52`

So required number are
`6^2=36 => 63`

`7^2=49 => 94`

`8^2=64 => 46`

Answer : `63,94,46`

`:.` The next 3 number for given series `1,4,9,61,52` are `63,94,46`

Solution-1

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3. Find next 3 numbers in the sequence `72,46,521,612,343`

Here each number is reverse of the cube of the numbers
`3^3=27 => 72`

`4^3=64 => 46`

`5^3=125 => 521`

`6^3=216 => 612`

`7^3=343 => 343`

So required number are
`8^3=512 => 215`

`9^3=729 => 927`

`10^3=1000 => 0001`

Answer : `215,927,0001`

`:.` The next 3 number for given series `72,46,521,612,343` are `215,927,0001`

Solution-1

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4. Find next 3 numbers in the sequence `11,31,71,91,32,92`

Here each number is reverse of the prime number
`5" prime "=11 => 11`

`6" prime "=13 => 31`

`7" prime "=17 => 71`

`8" prime "=19 => 91`

`9" prime "=23 => 32`

`10" prime "=29 => 92`

So required number are
`11" prime "=31 => 13`

`12" prime "=37 => 73`

`13" prime "=41 => 14`

Answer : `13,73,14`

`:.` The next 3 number for given series `11,31,71,91,32,92` are `13,73,14`

Solution-1

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5. Find next 3 numbers in the sequence `18,46,94,63`

`18,46,94,63,...`

First reverse the digits of each number
`81,64,49,36,...`

Here each number is square of numbers in descending order
The next term will be `25,16,9`

So after reversing it, the answer will be `52,61,9`

`:.` The next 3 number for given series `18,46,94,63` are `52,61,9`

Solution-1

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6. Find next 3 numbers in the sequence `215,343,612,521,46`

`215,343,612,521,46,...`

First reverse the digits of each number
`512,343,216,125,64,...`

Here each number is cube of the numbers in descending order
The next term will be `27,8,1`

So after reversing it, the answer will be `72,8,1`

`:.` The next 3 number for given series `215,343,612,521,46` are `72,8,1`

Solution-1

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