|
|
|
|
|
|
|
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
|
|
Pivots of a Matrix calculator
|
 1. `[[8,-6,2],[-6,7,-4],[2,-4,3]]`
2. `[[3,2,4],[2,0,2],[4,2,3]]`
3. `[[1,1,1],[-1,-3,-3],[2,4,4]]`
4. `[[1,2,3],[0,1,0],[2,3,1]]`
5. `[[1,2,1],[6,-1,0],[-1,-2,-1]]`
6. `[[6,-2,2],[-2,3,-1],[2,-1,3]]`
7. `[[2,3],[4,10]]`
8. `[[5,1],[4,2]]`
9. `[[6,3],[4,5]]`
|
Example1. Find Pivots of a Matrix ...
`[[8,-6,2],[-6,7,-4],[2,-4,3]]`Solution:First apply Gaussian Elimination method to find Pivots | `A` | = | | `8` | `-6` | `2` | | | `-6` | `7` | `-4` | | | `2` | `-4` | `3` | |
|
`R_2 larr R_2+3/4xx R_1` | = | | `8` | `-6` | `2` | | | `0` | `5/2` | `-5/2` | | | `2` | `-4` | `3` | |
|
`R_3 larr R_3-1/4xx R_1` | = | | `8` | `-6` | `2` | | | `0` | `5/2` | `-5/2` | | | `0` | `-5/2` | `5/2` | |
|
`R_3 larr R_3+ R_2` | = | | `8` | `-6` | `2` | | | `0` | `5/2` | `-5/2` | | | `0` | `0` | `0` | |
|
Pivots are the first non-zero element in each row of this eliminated matrix. `:.` Pivots are `8,5/2` |
|
|
|
|
|
