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Solution
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Solution provided by AtoZmath.com
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value of determinant using properties of determinants calculator
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 1. `[[2,5,7],[6,15,21],[1300,1248,1871]]`
2. `[[201,210,220],[151,155,140],[50,55,80]]`
3. `[[2,1970,1978],[5,1960,1980],[7,1950,1978]]`
4. `[[1977,1979,1981],[1940,1943,1946],[10,17,24]]`
5. `[[6,3,9],[1,0,2],[40,50,20]]`
6. `[[100,205,105],[200,408,207],[300,608,310]]`
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Example1. Find value of determinant using properties of determinants ...
`[[201,210,220],[151,155,140],[50,55,80]]`Solution:| `A=` | | 201 | 210 | 220 | | | 151 | 155 | 140 | | | 50 | 55 | 80 | |
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Now, `R_1=R_1 - R_2` | `=` | | 50 | 55 | 80 | | | 151 | 155 | 140 | | | 50 | 55 | 80 | |
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Here `R_3=R_1`, So value of the determinant is 0 `=0` Method-2: Determinant by expanding cofactors| `|A|` | = | | `201` | `210` | `220` | | | `151` | `155` | `140` | | | `50` | `55` | `80` | |
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`=201 xx (155 × 80 - 140 × 55) -210 xx (151 × 80 - 140 × 50) +220 xx (151 × 55 - 155 × 50)` `=201 xx (12400 -7700) -210 xx (12080 -7000) +220 xx (8305 -7750)` `=201 xx (4700) -210 xx (5080) +220 xx (555)` `= 944700 -1066800 +122100` `=0` |
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