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Method and examples
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Method |
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Inverse of matrix using
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- `[[2,3,1],[0,5,6],[1,1,2]]`
- `[[2,1,-1],[1,0,-1],[1,1,2]]`
- `[[3,1,1],[-1,2,1],[1,1,1]]`
- `[[2,3],[4,10]]`
- `[[5,1],[4,2]]`
- `[[6,3],[4,5]]`
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Method
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Solving systems of linear equations using
Gauss Elimination Back Substitution method
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Enter Equations line by line like
2x+5y=16
3x+y=11
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Or
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2, 5, 16
3, 1, 11
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Or
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(8-18.1906i), (-2+13.2626i), 100
(2-13.2626i), (1+14.7706i), 0
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Initial gauss / Start value = ( )
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w =
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Convert to Diagonnay Dominant Equation (if required) =
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- `2x+y+z=5,3x+5y+2z=15,2x+y+4z=8`
- `2x+5y=16,3x+y=11`
- `2x+5y=21,x+2y=8`
- `2x+y=8,x+2y=1`
- `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`
- `x+y+z=3,2x-y-z=3,x-y+z=9`
- `x+y+z=7,x+2y+2z=13,x+3y+z=13`
- `2x-y+3z=1,-3x+4y-5z=0,x+3y-6z=0`
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Mode =
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Decimal Place =
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Click here to Find the value of h,k for which the system of equations has a Unique or Infinite or no solution calculator
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Solution
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Solution provided by AtoZmath.com
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Solving systems of linear equations using Gauss Elimination Back Substitution method calculator
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 1. `2x+y+z=5,3x+5y+2z=15,2x+y+4z=8`
2. `2x+5y=16,3x+y=11`
3. `2x+5y=21,x+2y=8`
4. `2x+y=8,x+2y=1`
5. `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`
6. `x+y+z=3,2x-y-z=3,x-y+z=9`
7. `x+y+z=7,x+2y+2z=13,x+3y+z=13`
8. `2x-y+3z=1,-3x+4y-5z=0,x+3y-6z=0`
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