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1.
Matrix Algebra
on 17.03.19
1.
with variables
`[[2x,3y],[3x,4z]]`
2.
with complex numbers
`[[-5i,3i],[4i,5i]]`
3.
with surds
`[[1/sqrt(2),sqrt(2)],[4,-5]]`
2. PERT and CPM
1.
Network diagram
on 10.03.19
2.
Critical path, Total float, Free float, Independent float
on 10.03.19
3.
Project scheduling with uncertain activity times (Optimistic, Most likely, Pessimistic)
on 10.03.19
4.
Project crashing to solve Time-Cost Trade-Off with fixed Indirect cost
on 10.03.19
5.
Project crashing to solve Time-Cost Trade-Off with varying Indirect cost
on 10.03.19
2. Transportation Problem
3.
Heuristic method-1
on 07.01.19
4.
Heuristic method-2
on 07.01.19
5.
Row minima method
on 24.12.18
6.
Column minima method
on 24.12.18
7.
Russell's approximation method
on 24.12.18
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Method and examples
Installment
1. A briefcase is available for Rs 800 cash or for Rs 500 cash down payment and Rs 320 to be paid after 6 months. Find the rate ...
2. A bicycle is sold for Rs 1800 cash or for Rs 600 cash down payment followed by 2 monthly installmnets of Rs 610 each. Compute ...
3. A washing machine is available at Rs 6400 cash or for Rs 1400 cash down payment and 5 monthly installments of Rs 1030 each. C ...
4. A computer is sold by a company for Rs 19200 cash or for Rs 4800 cash down payment together with 5 equal monthly installments ...
5. A State Government announces sale of flats of Rs 555000 cash or Rs 42750 cash down payment and 3 equal Yearly installments. T ...
6. A TV set is available for Rs 19650 cash payment or for Rs 3100 cash down payment and 3 equal Yearly installments. If the shop ...
7. A man borrows money from a finance company and has to pay it back in 2 equal Half Yearly installments of Rs 4945 each. If the ...
8. Ram borrowed a sum of money and returned it in 3 equal Quarterly installments of Rs 17576 each. Find the sum borrowed, if the ...
Problem 4 of 8
4. A computer is sold by a company for Rs
cash or for Rs
cash down payment together with
equal monthly installments. If the rate of interest charged by the company is
% per annum, find each installment.
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Installment
4. A computer is sold by a company for Rs 19200 cash or for Rs 4800 cash down payment together with 5 equal monthly installments. If the rate of interest charged by the company is 12 % per annum, find each installment.
Cash Price = `19200`
Down Payemnt = `4800`
Number of Installment = `5`
Rate = `12`
Remaining Balance = `19200 - 4800 = 14400`
At the end of `5` months, Amounts to = `14400 + (14400 × 5 × 12) /(12 × 100) = 14400 + 720`
` = 15120 ->(1)`
Let Installment = `X`
`1^(st)` Installment `= X + (12 × X × 4) / (12 × 100)`
`2^(nd)` Installment `= X + (12 × X × 3) / (12 × 100)`
`3^(rd)` Installment `= X + (12 × X × 2) / (12 × 100)`
`4^(th)` Installment `= X + (12 × X × 1) / (12 × 100)`
Total Installment `= X + ( X + (12 × X × 4) / (12 × 100) ) + ( X + (12 × X × 3) / (12 × 100) ) + ( X + (12 × X × 2) / (12 × 100) ) + ( X + (12 × X × 1) / (12 × 100) )`
Total Installment `= 5 X + (12 × X ×(4 + 3 + 2 + 1))/ (12 × 100)`
Total Installment `= 5 X + 1/10 × X`
Total Installment `= 51/10 X ->(2)`
From (1) and (2)
`51/10 X = 15120`
`X = (15120) / (51/10)`
`X = 50400/17`
`:.` Installment Amount = `50400/17`
OR METHOD
Cash Price = `19200`
Down Payemnt = `4800`
Number of Installment = `5`
Rate = `12`
Remaining Balance = `19200 - 4800 = 14400`
Let Installment = `X`
`:.` Interest Paid = `5 X - 14400 ->(1)`
Principal for `1^(st)` month = `14400`
Principal for `2^(nd)` month = `14400 - 1 X`
Principal for `3^(rd)` month = `14400 - 2 X`
Principal for `4^(th)` month = `14400 - 3 X`
Principal for `5^(th)` month = `14400 - 4 X`
Total `= 72000 - 10 X`
`:.` Interest `= ((72000 - 10 X) × 12 × 1) / (100 × 12) ->(2)`
`:.` From (1) and (2)
`((72000 - 10 X) × 12 × 1) / (100 × 12) = 5 X - 14400`
`(72000 - 10 X) = 500 X - 1440000`
`500 X + 10 X = 72000 + 1440000`
`510 X = 1512000`
`:. X = 50400/17`
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