


Method and examples


HCF_LCM 



Problem 6 of 11 


6. Greatest no which can divide , and leaving the same remainder in each case.










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HCF_LCM 
6. Greatest no which can divide 1354 , 1806 and 2762 leaving the same remainder 10 in each case.
The number divides 1354 and leaves 10 as remainder `:.` The number exactly divides 1354  10 = 1344
The number divides 1806 and leaves 10 as remainder `:.` The number exactly divides 1806  10 = 1796
The number divides 2762 and leaves 10 as remainder `:.` The number exactly divides 2762  10 = 2752
Now, we have to find HCF of `1344, 1796, 2752`
Find HCF of (1344,1796)
    
 1344             
 
                    
 
                          
 
                              
                               
 
                                      
 
                                          
              
HCF of (1344, 1796) = 4
Now find HCF of (4,2752)
HCF of (4, 2752) = 4
`:.` HCF of given numbers (1344,1796,2752) = 4
`:.` Required number = HCF of `1344, 1796, 2752 = 4`.







